A particle is dropped from a height of
100 m and another particle is projected vertically up with velocity 50 m/s from
the ground along the same line. Find out the position where two particles will
meet?

Let the upward direction is positive. And imagine the particles will meet at a
distance y from the ground.

For particle A,

Y

_{0}= +100 m
u = 0 m/sec

a = -10 m/sec2

We
know,

Y

_{0}= 0 m
u = +50 m/sec

a = -10 m/sec2

Also,
From (1) and (2), by
equating, we will get

t = 2 sec.

By putting t =2 sec in
equation (1) or (2), you will get, y =80 m.

It means, the particle
will meet at a height of 80 m from ground.

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