A particle is dropped from a height of 100 m and another particle is projected vertically up with velocity 50 m/s from the ground along the same line. Find out the position where two particles will meet?
Let the upward direction is positive. And imagine the particles will meet at a distance y from the ground.
For particle A,
Y0 = +100 m
u = 0 m/sec
a = -10 m/sec2
Y0 = 0 m
u = +50 m/sec
a = -10 m/sec2Also,
From (1) and (2), by equating, we will get
t = 2 sec.
By putting t =2 sec in equation (1) or (2), you will get, y =80 m.
It means, the particle will meet at a height of 80 m from ground.